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x^2-240x=-950
We move all terms to the left:
x^2-240x-(-950)=0
We add all the numbers together, and all the variables
x^2-240x+950=0
a = 1; b = -240; c = +950;
Δ = b2-4ac
Δ = -2402-4·1·950
Δ = 53800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{53800}=\sqrt{100*538}=\sqrt{100}*\sqrt{538}=10\sqrt{538}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-240)-10\sqrt{538}}{2*1}=\frac{240-10\sqrt{538}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-240)+10\sqrt{538}}{2*1}=\frac{240+10\sqrt{538}}{2} $
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